Problem 01.
A drug has a volume of distribution of 300 L in a 500 Kg
horse.
- What is its Vd in L/Kg?
Problem
02. A drug has a volume of
distribution of 0.3 L/Kg. [Student
Question]
- What is the total Vd in a 15 Kg Beagle?
- What is the total Vd in a 40 pound Beagle?
Problem
03. A drug was given IV to a 70
Kg calf at a dose of 2.5 mg/Kg. Concentrations of drug in
plasma were found to be the as follows (mg/L): 2 hr = 7.07; 4
hr = 5.00; 6 hr = 3.54; 8 hr = 2.50.
- What is the total dose?
- What is the Cp(0)?
- What is the Vd/Kg?
- What is the whole animal Vd?
Problem
04. A drug was given IV to a 3
Kg cat at a dose of 5 mg/Kg. The resulting Cp(0) was 20 mg/L.
The same dose of drug was given to the cat 1 month later by
mouth and the animal had no significant change in weight or
hydration status. The resulting Cp(0) was 17 mg/L. Assume
both of these values were "correct." [Student
Question]
- What is the approximate F?
- What formula did you use to calculate F?
- How does it compare to the approach described in
class?
Problem 05.
A drug was given IV to an animal that had an estimated Vd of
0.9 L/Kg. The dose was 4 mg/Kg.
- What is the estimated Cp(0)?
- What is the estimate of F?
- How does this Cp(0) correspond to the "A"
in the one-compartment pharmacokinetic model?
Problem 06.
A drug was given PO to an animal that had an estimated Vd of
0.6 L/Kg. The dose was 3 mg/Kg and the literature states the
F for this drug give PO is 0.8.
- What is the highest possible value for Cp(0) in this
case?
- Is the actual value going to be higher or lower that
this?
(Remember Cp(0) in this case would be the
extrapolated value.)
Problem 07.
You are treating a 25 pound terrier with a drug that has a Vd
of 0.4 L/Kg and you want the concentration to be in the range
of 15 mg/L.
- How much drug should you give IV for the initial dose
(LD)?
Problem 08.
You are treating a 15 Kg dog with a drug that has a Vd of 0.3
L/Kg, a PO F=0.6, and you want a Cp(0) of 10 mg/L.
- How much drug should you give PO to this dog?
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Last modified: 05 Sep 1996 18:39 glc